
StraightLine
Equations: Sections: Slopeintercept form, Pointslope form, Parallel and perpendicular lines Straightline equations, or "linear" equations, graph as straight lines, and have simple variable expressions with no exponents on them. If you see an equation with only x and y — as opposed to, say x^{2} or sqrt(y) — then you're dealing with a straightline equation. There are different types of "standard" formats for straight lines; the particular "standard" format your book refers to may differ from that used in some other books. (There is, ironically, no standard definition of "standard form".) The various "standard" forms are often holdovers from a few centuries ago, when mathematicians couldn't handle very complicated equations, so they tended to obsess about the simple cases. Nowadays, you likely needn't worry too much about the "standard" forms; this lesson will only cover the morehelpful forms. I think the most useful form of straightline equations is the "slopeintercept" form: y = mx + b This is called the slopeintercept form because "m" is the slope and "b" gives the yintercept. (For a review of how this equation is used for graphing, look at slope and graphing.) I like slopeintercept form the best. It is in the form "y=", which makes it easiest to plug into, either for graphing or doing word problems. Just plug in your xvalue; the equation is already solved for y. Also, this is the only format you can plug into your (nowadays obligatory) graphing calculator; you have to have a "y=" format to use a graphing utility. But the best part about the slopeintercept form is that you can read off the slope and the intercept right from the equation. This is great for graphing, and can be quite useful for word problems. Copyright © Elizabeth Stapel 20002011 All Rights Reserved Common exercises will give you some pieces of information about a line, and you will have to come up with the equation of the line. How do you do that? You plug in whatever they give you, and solve for whatever you need, like this:
Okay, they've given me the value of the slope; in this case, m = 4. Also, in giving me a point on the line, they have given me an xvalue and a yvalue for this line: x = –1 and y = –6. In the slopeintercept form of a straight line, I have y, m, x, and b. So the only thing I don't have so far is a value for is b (which gives me the yintercept). Then all I need to do is plug in what they gave me for the slope and the x and y from this particular point, and then solve for b: y = mx
+ b Then the line equation must be "y = 4x – 2". What if they don't give you the slope?
Well, if I have two points on a straight line, I can always find the slope; that's what the slope formula is for. Now I have the slope and two points. I know I can find the equation (by solving first for "b") if I have a point and the slope. So I need to pick one of the points (it doesn't matter which one), and use it to solve for b. Using the point (–2, 4), I get:
y = mx + b ...so y = ( –^{ 2}/_{3 }) x + ^{8}/_{3}. On the other hand, if I use the point (1, 2), I get: y = mx + b So it doesn't matter which point I choose. Either way, the answer is the same: y = (–^{ 2}/_{3})x + ^{8}/_{3} As you can see, once you have the slope, it doesn't matter which point you use in order to find the line equation. The answer will work out the same either way. Top  1  2  3  Return to Index Next >>


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