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Special Factoring:
     Factoring Differences of Squares
(page 1 of 3)

Sections: Differences of squares, Sums and differences of cubes, Recognizing patterns


When you learn to factor quadratics, there are three other formulas that they usually introduce at the same time. The first is the "difference of squares" formula.

Remember from your translation skills that "difference" means "subtraction". So a difference of squares is something that looks like x2 – 4. That's because 4 = 22, so you really have x2 – 22, a difference of squares. To factor this, do your parentheses, same as usual:

    x2 – 4 = (x      )(x     )

You need factors of –4 that add up to zero, so use –2 and +2

    x2 – 4 = (x – 2)(x + 2)

(Review Factoring Quadratics, if this doesn't make sense to you.)


Note that we had x2 – 22, and ended up with (x 2)(x + 2). Differences of squares (something squared minus something else squared) always work this way:

    For a2b2, do the parentheses:

      (         )(        )

    ...put the first squared thing in front:

      (a      )(a       )

    ...put the second squared thing in back:

      (a    b)(a     b)

    ...and alternate the signs:

      (ab)(a + b)

Memorize this! It really does come in handy, especially when you get to rational expressions (polynomial fractions).


Here are examples of some typical homework problems:

  • Factor x2 – 16

    This is x2 – 42, so I get:

      x2 – 16 = x2 – 42 = (x – 4)(x + 4)

  • Factor 4x2 – 25

    This is (2x)2 – 52, so I get:

      4x2 – 25 = (2x)2 – 52 = (2x – 5)(2x + 5)

  • Factor 9x6 y8

    This is (3x3)2 – (y4)2, so I get:

      9x6y8 = (3x3)2 – (y4)2 = (3x3y4)(3x3 + y4)

  • Factor x4 – 1 Copyright © Elizabeth Stapel 2006-2008 All Rights Reserved

    This is (x2)2 – 12, so I get:

      x4 – 1 = (x2)2 – 12 = (x2 – 1)(x2 + 1)

    Note that I'm not done yet, because x2 – 1 is itself a difference of squares, so I need to apply the formula again, to get:

      x4 – 1 = (x2)2 – 12 = (x2 – 1)(x2 + 1)

                = ((x)2 – (1)2)(x2 + 1)

                = (x 1)(x + 1)(x2 + 1)

This last answer depended on the fact that 1, to any power at all, is still just 1. And never forget that this formula is for the difference of squares; the sum of squares is always prime (that is, it can't be factored).

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Cite this article as:

Stapel, Elizabeth. "Special Factoring: Factoring Differences of Squares." Purplemath. Available from
    http://www.purplemath.com/modules/specfact.htm. Accessed
 

 

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