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Scalar and Matrix Multiplication (page 1 of 3) There are two types of multiplication for matrices: scalar multiplication and matrix multiplication. Scalar multiplication is easy. You just take a regular number (called a "scalar") and multiply it on every entry in the matrix.
To do the first scalar multiplication to find 2A, I just multiply a 2 on every entry in the matrix: The other scalar multiplication, to find –1A, works the same way: So the final answer is: Copyright © Elizabeth Stapel 20032011 All Rights Reserved Scalar multiplication is easy. Matrix multiplication, however, is quite another story. In fact, it's a royal pain. Your text probably gave you a complex formula for the process, and that formula probably didn't make any sense to you. That's okay. The process is messy, and that complicated formula is the best they can do for an explanation in a formal setting like a textbook. Here's how the process works:
To calculate AB, I write down A and B next to each other like this: Now I need to multiply the ROWS of A by the COLUMNS of B. By this I mean that I first take the first row of A and the first column of B, and I multiply the first entries, then the second entries, and then the third entries, and then I add the three products. The sum is one entry in the product matrix AB; in fact, being the product of row 1 and column 1, the result is the 1,1entry of AB. Then I continue in like manner. For instance, the sum of the products from row 2 of A and column 1 of B is the 2,1entry of AB. When I multiply matrices, I use my fingers to keep track of what I'm doing. The following animation is my attempt to illustrate this process. (Don't laugh; I'm no artist!) (Now, class; what did I say about laughing?) The final answer is: As you saw on the above example, the general rule is that the product of the ith row of A and the jth column of B is the i,jth entry of the product matrix AB. This general rule is, in large part, what that complicated formula in your text was all about. For instance, when I, in the above example, multiplied the first row (of A) and the second column (of B), this gave me the firstrowsecondcolumn entry in the product matrix AB. Top  1  2  3  Return to Index Next >>



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