...Suppose that R on A is antisymmetric. Let R = {(m, n): m, n ? A}. Therefore, by definition of inverse relation, R-1 = {(n, m): m, n ? A}. Let (m, n) ? (R n R-1). By definition of intersection, (m, n) ? R and (m, n) ? R-1. Because (m, n) ? R-1, (n, m) ? R. (read more)
...I taught middle and high school mathematics for 5 years and decided to pursue a graduate degree. I completed my Master's in mathematics education from Syracuse University and I am currently a PhD candidate in mathematics education on track to complete my PhD in July 2024. My teaching methodolo... (read more)