The "interquartile range", abbreviated "IQR", is just the width of the box in the box-and-whisker plot. That is, IQR = Q3 − Q1 . The IQR can be used as a measure of how spread-out the values are.
Statistics assumes that your values are clustered around some central value. The IQR tells how spread out the "middle" values are; it can also be used to tell when some of the other values are "too far" from the central value. These "too far away" points are called "outliers", because they "lie outside" the range in which we expect them.
The IQR is the length of the box in your box-and-whisker plot. An outlier is any value that lies more than one and a half times the length of the box from either end of the box.
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That is, if a data point is below Q1 − 1.5×IQR or above Q3 + 1.5×IQR, it is viewed as being too far from the central values to be reasonable. Maybe you bumped the weigh-scale when you were making that one measurement, or maybe your lab partner is an idiot and you should never have let him touch any of the equipment. Who knows? But whatever their cause, the outliers are those points that don't seem to "fit".
You can use the Mathway widget below to practice finding the Interquartile Range, also called "H-spread" (or skip the widget and continue with the lesson). Try the entered exercise, or type in your own exercise. Then click the button and scroll down to "Find the Interquartile Range (H-Spread)" to compare your answer to Mathway's.
(Click "Tap to view steps" to be taken directly to the Mathway site for a paid upgrade.)
Once you're comfortable finding the IQR, you can move on to locating the outliers, if any.
10.2, 14.1, 14.4. 14.4, 14.4, 14.5, 14.5, 14.6, 14.7, 14.7, 14.7, 14.9, 15.1, 15.9, 16.4
To find out if there are any outliers, I first have to find the IQR. There are fifteen data points, so the median will be at the eighth position:
(15 + 1) ÷ 2 = 8
Then Q2 = 14.6.
There are seven data points on either side of the median. The two halves are:
10.2, 14.1, 14.4. 14.4, 14.4, 14.5, 14.5
14.7, 14.7, 14.7, 14.9, 15.1, 15.9, 16.4
Q1 is the fourth value in the list, being the middle value of the first half of the list; and Q3 is the twelfth value, being th middle value of the second half of the list:
Q1 = 14.4
Q3 = 14.9
Then the IQR is given by:
IQR = 14.9 − 14.4 = 0.5
Outliers will be any points below Q1 − 1.5 ×IQR = 14.4 − 0.75 = 13.65 or above Q3 + 1.5×IQR = 14.9 + 0.75 = 15.65.
Then the outliers are at:
10.2, 15.9, and 16.4
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The values for Q1 − 1.5×IQR and Q3 + 1.5×IQR are the "fences" that mark off the "reasonable" values from the outlier values. Outliers lie outside the fences.
If your assignment is having you consider not only outliers but also "extreme values", then the values for Q1 − 1.5×IQR and Q3 + 1.5×IQR are the "inner" fences and the values for Q1 − 3×IQR and Q3 + 3×IQR are the "outer" fences.
The outliers (marked with asterisks or open dots) are between the inner and outer fences, and the extreme values (marked with whichever symbol you didn't use for the outliers) are outside the outer fences.
By the way, your book may refer to the value of " 1.5×IQR " as being a "step". Then the outliers will be the numbers that are between one and two steps from the hinges, and extreme value will be the numbers that are more than two steps from the hinges.
Looking again at the previous example, the outer fences would be at 14.4 − 3×0.5 = 12.9 and 14.9 + 3×0.5 = 16.4. Since 16.4 is right on the upper outer fence, this would be considered to be only an outlier, not an extreme value. But 10.2 is fully below the lower outer fence, so 10.2 would be an extreme value.
Your graphing calculator may or may not indicate whether a box-and-whisker plot includes outliers. For instance, the above problem includes the points 10.2, 15.9, and 16.4 as outliers. One setting on my graphing calculator gives the simple box-and-whisker plot which uses only the five-number summary, so the furthest outliers are shown as being the endpoints of the whiskers:
A different calculator setting gives the box-and-whisker plot with the outliers specially marked (in this case, with a simulation of an open dot), and the whiskers going only as far as the highest and lowest values that aren't outliers:
My calculator makes no distinction between outliers and extreme values. Yours may not, either. Check your owner's manual now, before the next test.
If you're using your graphing calculator to help with these plots, make sure you know which setting you're supposed to be using and what the results mean, or the calculator may give you a perfectly correct but "wrong" answer.
21, 23, 24, 25, 29, 33, 49
To find the outliers and extreme values, I first have to find the IQR. Since there are seven values in the list, the median is the fourth value, so:
Q2 = 25
The first half of the list is:
21, 23, 24
...so Q1 = 23; the second half is:
29, 33, 49
...so Q3 = 33. Then the IQR is given by:
IQR = 33 − 23 = 10
The outliers will be any values below:
23 − 1.5×10 = 23 − 15 = 8
33 + 1.5×10 = 33 + 15 = 48
The extreme values will be those below:
23 − 3×10 = 23 − 30 = −7
33 + 3×10 = 33 + 30 = 63
So I have an outlier at 49 but no extreme values. I won't have a top whisker on my plot because Q3 is also the highest non-outlier. So my plot looks like this:
It should be noted that the methods, terms, and rules outlined above are what I have taught and what I have most commonly seen taught. However, your course may have different specific rules, or your calculator may do computations slightly differently. You may need to be somewhat flexible in finding the answers specific to your curriculum.