The current flowing through an inductor of self-inductance L is continuously increasing. Plot a graph showing the variation of

Induced emf versus dI/dt

Advertisement Remove all ads

#### Solution

Induced emf,

`e=(dphi)/dt=-d/dt(LI)`

i.e `e=-L(dI)/dt`

Concept: Induced Emf and Current

Is there an error in this question or solution?

#### APPEARS IN

Advertisement Remove all ads