- #1

- 45

- 0

Ok, so for Q6, I first said that

z = 3 - 3x - 1.5y

Using (∂z/∂x)^2 = 9, (∂z/∂y)^2 = 9/4

I then did a double integral of (x + y + (3 - 3x - 1.5y)) * sqrt(9 + 9/4 + 1) dA

Letting y and x be bounded below by 0 as stated, and x bounded above by 1 - 0.5y and y bounded above by 2, I went through the integral and got out 28.

Using pretty much the exact same method for Q7 I got the answer to be 2.

This is the first time attempting these sort of questions, really not sure if I'm doing it right. They only take a few minutes to do, so was hoping someone who was more confident in what they were doing could just check this for me, and let me know if I'm actually on the right track or not. Thanks a lot.