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A person pushes a 2.0 kg box across a flat, horizontal surface with a force of 5.0 N for 4.0 m. Determine the acceleration of a box if the friction coefficient is 0.2.

Determine the acceleration of the box if the friction coefficient is 0.2.

First, we need to find the static force.

[tex] F_s= \mu F_n = (0.2) (2 \cdot 9.81) = 3.924 \ N [/tex]

Then, we need to find the net force.

[tex] F_{net} = 5 \ N - 3.924 \ N = 1.076 \ N[/tex]

Then, finally, the acceleration of the box is:

[tex] F=ma \Rightarrow 1.076 = (2 \ kg) \ a \Rightarrow \boxed{a=0.538 m/s^2}[/tex]

Is that right? Any help is appreciated.