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## Homework Statement

Find the area of the region between the curves f(x) = 3x^2 and g(x) = sqrt(x/3) for 0 <= x <= 1.

## Homework Equations

## The Attempt at a Solution

So.. since g(x) is greater than f(x) from 0 to 1/3, and less from 1/3 to 1.

I set up the integrals

[int. from 0 to 1/3 of g(x) - int. from 0 to 1/3 of f(x)] + [int. from 1/3 to 1 of f(x) - int. from 1/3 to 1 of g(x)]

Is that set up correctly?

Next is where my problem is...

integral of 3x^2 is x^3, but how do I integrate sqrt(x/3) ?

I used the power rule and got [2(x/3)^3/2]/3, but that doesn't seem right, please help me out with this.

Thanks!