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Well, I'm quite idle in Lunar New year's holidays so I decide to do some exercises on Physics, I got stuck when solving the problem, then I tried with the suggestion on my text book, but still, I don't understand the problem, please help me out! btw, sorry, something has gotten on LaTex or I'm too bad at it, so I just place the raw syntax, sorry!

Well, we have the figure:

http://img.photobucket.com/albums/v649/maxpayne_lhp2/5.jpg

And also, we have:

[tex]\emf=48V, r(Internam resistance)=0\omega[/tex]

[tex]R_1=2\onega[/tex]

[tex]R_2=8\onega\][/tex]

[tex]R_3=6\onega[/tex]

[tex]R_4=16\onega[/tex]

Well, they told me to find out the value of [tex]U_{MN}[/tex] (Well, in my native scientific system taugh in school,[tex] U_{MN} [/tex]stands for the potential diferece between M and N.

Well, obviously, I found that

[tex]U_{MN} = U_{MA}+U_{AN}[/tex]

[tex]=U_{AN}-U_{AM}[/tex]

Then, I tended to account for the Intensity of the current thru AB via the formula:

[tex]I=\frac{\emf}{R_{AB}}[/tex]

Then, I found out that I=8 (A)

But soon, I saw something wrong and looked up in the suggestion corner, they told me:

As r=0. we have

[tex]U_{MN}=\emf.[/tex] Let the current flows thru AMB and ANB from A to B, then:

[tex]U_{AN}=\frac{U_{AB}}{R_2+R_4} . R_2 = \frac{\emf}{R_2+R_4} . R_2= 16V[/tex]

Do the same thing with [tex]U_{AM}[/tex]

Though, I don't really understand what they mean, so please help me out! What did I do wrong?

Thanks for your time and help!

Well, we have the figure:

http://img.photobucket.com/albums/v649/maxpayne_lhp2/5.jpg

And also, we have:

[tex]\emf=48V, r(Internam resistance)=0\omega[/tex]

[tex]R_1=2\onega[/tex]

[tex]R_2=8\onega\][/tex]

[tex]R_3=6\onega[/tex]

[tex]R_4=16\onega[/tex]

Well, they told me to find out the value of [tex]U_{MN}[/tex] (Well, in my native scientific system taugh in school,[tex] U_{MN} [/tex]stands for the potential diferece between M and N.

Well, obviously, I found that

[tex]U_{MN} = U_{MA}+U_{AN}[/tex]

[tex]=U_{AN}-U_{AM}[/tex]

Then, I tended to account for the Intensity of the current thru AB via the formula:

[tex]I=\frac{\emf}{R_{AB}}[/tex]

Then, I found out that I=8 (A)

But soon, I saw something wrong and looked up in the suggestion corner, they told me:

As r=0. we have

[tex]U_{MN}=\emf.[/tex] Let the current flows thru AMB and ANB from A to B, then:

[tex]U_{AN}=\frac{U_{AB}}{R_2+R_4} . R_2 = \frac{\emf}{R_2+R_4} . R_2= 16V[/tex]

Do the same thing with [tex]U_{AM}[/tex]

Though, I don't really understand what they mean, so please help me out! What did I do wrong?

Thanks for your time and help!

Last edited: