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**vAn objects moves horizontally according to the following equation s(t)=t**

v'(t)= lim (s(t

h-->0

And

What is the average velocity of the object from t=0 to t=2?

Average velocity= (s(t

^{3}-2t^{2}-5t+6. Determine the instantaneous velocity of the object at t0=1 second using the definition of a derivative at a point.v'(t)= lim (s(t

_{0}+h)-s(t_{0}))/hh-->0

And

What is the average velocity of the object from t=0 to t=2?

Average velocity= (s(t

_{2})-s(t_{1}))/(t_{2}-t_{1})For the first one, i got:

((1+h)

^{3}-2(1+h)

^{2}-5(1+h)+6-1

^{3}-2(1)

^{2}-5(1)+6)/h

I expanded and factored all of that ang got (h(-1+h+h

^{2})/h then i plugged in 0 for h and got -1 as the instantaneous velocity... is that correct?

**I got the first one... i just added the values wrong... i got -6. But i still dont know how to do the second one.**

and for the second one, i have (3(2)

^{2}-4(2)-5)/2-0 but that makes it 0/2 and i know that this cant be.

Can you please help me?thank you!

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