- #1

- 190

- 0

I have problems on understanding Relativity.So can someone check this one.

A spacecraft is launched from the surface of the with velocity of 0.600c at an angle of

[tex]50^{\circle}[/tex] above the horizontal positive x axis.Another spacecraft is moving past,with a velocity of 0.700c in the negative x direction..Determine the magnitude of and direction of the velocity of the first spacecraft as measured by the pilot of the second spacecraft.

[tex]v_{1x}=0.6c\times cos50^{\circle}[/tex]

[tex]v'_x=\frac{v_{1x}+v_2}{1+\frac{v_{1x}v_2}{c^2}}[/tex]

[tex]v'_y=v_1sin50^{\circle}[/tex]

[tex]v'=\sqrt{v'_x+v'_y}[/tex]

[tex]tan\theta'=\frac{v'_y}{v'_x}[/tex]

## Homework Statement

## Homework Equations

A spacecraft is launched from the surface of the with velocity of 0.600c at an angle of

[tex]50^{\circle}[/tex] above the horizontal positive x axis.Another spacecraft is moving past,with a velocity of 0.700c in the negative x direction..Determine the magnitude of and direction of the velocity of the first spacecraft as measured by the pilot of the second spacecraft.

## The Attempt at a Solution

[tex]v_{1x}=0.6c\times cos50^{\circle}[/tex]

[tex]v'_x=\frac{v_{1x}+v_2}{1+\frac{v_{1x}v_2}{c^2}}[/tex]

[tex]v'_y=v_1sin50^{\circle}[/tex]

[tex]v'=\sqrt{v'_x+v'_y}[/tex]

[tex]tan\theta'=\frac{v'_y}{v'_x}[/tex]

Last edited by a moderator: