- Tue May 13, 2014 9:53 pm
- Forum: Pre-Algebra
- Topic: Compound Interest
- Replies:
**3** - Views:
**3649**

I copied the text verbatim from the textbook. I'm aware of all the possible "real life" variables that may form part of the equation, but in this instance I suppose it's a bit more elementary. I'm really just hoping someone can tell me whether I'm wrong or right in my calculation.

- Tue May 13, 2014 6:20 pm
- Forum: Pre-Algebra
- Topic: Compound Interest
- Replies:
**3** - Views:
**3649**

My calculations below are not included on the list of possible answers. John borrowed money from Stan. He has to pay Stan R500 three months from now and R930 five months from now. Stan charges him an interest rate of 20% per annum, compounded monthly. John decides to pay Stan back what he owes him t...

- Tue Feb 25, 2014 2:52 pm
- Forum: Intermediate Algebra
- Topic: Simplification of complex fractions.
- Replies:
**2** - Views:
**2081**

Voilà! I completely (ashamedly) missed that. Thanks.

- Tue Feb 25, 2014 8:21 am
- Forum: Intermediate Algebra
- Topic: Simplification of complex fractions.
- Replies:
**2** - Views:
**2081**

This is my attempt at simplification below: \frac{(8^x)(8^{3x})}{(2^{3x})(4^{x+2})} = \frac{8^{4x}}{(2^{3x})(2^{2x})(2^4)} = \frac{2^{12x}}{(2^{3x})(2^{2x})(2^4)} = (2^{12x})(2^{-3x})(2^{-2x})(2^{-4}) = (2^{12x-3x-2x})(2^{-4}) = (2^{7x})(\frac{1}{16}) The revision handbook gives the following as opt...