...Suppose R n R-1 ? {(a, a): a ? A}. Let R = {(x, y): x, y ? A}. By definition of inverse relation, R-1 = {(y, x): x, y ? A}. By definition of subset, if (x, y) ? R n R-1, (x, y) ? {(a, a): a ? A}. Hence, x = y, and so (x, y) ? R implies (y, x) ? R. Since x = y, ? (xRy ? yRx), x = y. Thus, by definition of antisymmetric, R on A is antisymmetric. (read more)
...I completed my Master's in mathematics education from Syracuse University and I am currently a PhD candidate in mathematics education on track to complete my PhD in July 2024. My teaching methodology is focused on making mathematics accessible and relevant to students from diverse backgrounds b... (read more)