The change in the velocity is 11 m/s - 7m/s = 4 m/s.

The time is 2 seconds.

Recall that Acceleration = Change in velocity/time

Substituting the known values we get the acceleration =

\frac{4 \frac{m}{s}}{2s} = 2 \frac{m}{s^{2}}

So the cyclist's acceleration is 2 \frac{m}{s^{2}}

I found an answer from www.physicsclassroom.com

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