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Synthetic Division Examples (page 2 of 4) Sections: Introduction, Worked examples, Finding zeroes, Factoring polynomials
This problem never said anything about polynomials, factors, or zeroes, but this division says that, if you divide 2x4 – 3x3 – 5x2 + 3x + 8 by x – 2, then the remainder will be 2, and therefore x – 2 is not a factor of 2x4 – 3x3 – 5x2 + 3x + 8, and x = 2 is not a zero (that is, a root or x-intercept) of the initial polynomial. Copyright © Elizabeth Stapel 2006-2008 All Rights Reserved
This question is asking me, in effect, to convert an improper polynomial fraction into a polynomial mixed number. That is, we are being asked to do something similar to converting the improper fraction 17/5 to the mixed number 3 2/5, which is really the shorthand for the expression "3 + 2/5".
As you can see, the remainder is 68. Since I started with a polynomial of degree 3 and then divided by x – 3, I am left with a polynomial of degree 2. Then the bottom line represents 3x2 + 7x + 24 with remainder 68. Putting this in the required format, I get the answer as being:
It is always true that, when you use synthetic division, your answer (in the bottom row) will be of one degree less than what you'd started with, because you have divided out a linear factor. That was how I knew that my answer, denoted by the "3 7 24" in the bottom row, stood for a quadratic, since I had started with a cubic. << Previous Top | 1 | 2 | 3 | 4 | Return to Index Next >>
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