Inverses of Trigonometric Ratios
You've learned how to use trig ratios to solve right triangles, finding the lengths of the sides of triangles. But what if you have the sides, and need to find the angles? You know that you can take side lengths and find trig ratios, and you know you can find trig ratios (in your calculator) for angles. What is missing is a way to go from the ratios back to the original angles. And that is what "inverse trig" values are all about.
If you look at your calculator, you should see, right above the "SIN", "COS", "TAN" buttons, notations along the lines of "SIN–1", "COS–1", and "TAN–1", or possibly "ASIN", "ACOS", and "ATAN". These are what you'll use to find angles from ratios.
The first set of notations, with the "minus one" exponent, lists the inverse sine, the inverse cosine, and the inverse tangent. The second set of notations, with the "A" before each name, lists the arcsine, arccosine, and arctangent. These are two notations for exactly the same thing.
Grab your calculator, and take the sine
of some angle value between zero and ninety degrees. Whatever result you
get, do the inverse sine ("SIN–1") or the arcsine
("ASIN") of that value, and you should get the value you started
with. That's what the inverses of trig ratios do: they give you the angle
that goes with that trig ratio.
They've given me the opposite side from α and the hypotenuse, so I can form the sine ratio:
9/10 = sin(α) = 0.9
Plugging 0.9 into SIN–1 in my calculator, I get α = 64.15806724...
m(α) = 64°
How on earth am I supposed to find m and p when I only have one number for that triangle? All I have is the hypotenuse! Oh, wait...
I can use the angle and hypotenuse on the left-hand triangle to find the height p, and this will give me two numbers for the right-hand triangle. With that, I can find m.
The left-hand triangle has "opposite", hypotenuse, and angle, so I'll work with the sine ratio:
p/15 = sin(47°)
Now that I know p = 11, I can find the measure of angle m:
11/18 = sin(m°)
p = 11 and m° = 38°
Any time you have two sides of a triangle and need an angle, figure out the trig ratio that uses those two sides, and use the appropriate inverse button to find the angle that goes with that ratio. And remember to put the "degree" sign on your answer.
Original URL: http://www.purplemath.com/modules/invratio.htm Copyright 2009 Elizabeth Stapel; All Rights Reserved.
Copyright 2009 Elizabeth Stapel; All Rights Reserved.