graphing with tan: y = tan(pi*x) + 2

[thewitch]

Now i know this is probably a basic question so please forgive me.
i have a problem y = tan(pi*x) + 2
iv established my points as x = -3pi/2 -pi/2 -pi/4 0 pi/4 pi/2 and 3pi/4 the problem is I don't quite grasp what would happen to my x points when i multiply them by pi an explanation would be great and thanks in advance for your help i can pretty much figure it out from there once i know what that initial pi*x is

[FWT]

i have a problem y = tan(pi*x) + 2

This is just an equation. What do the instructions say you're supposed to do with it? Are you supposed to be graphing this for some interval they give you?

iv established my points as x = -3pi/2 -pi/2 -pi/4 0 pi/4 pi/2 and 3pi/4

I dont know what that means???

the problem is I don't quite grasp what would happen to my x points when i multiply them by pi

I dont understand what you're asking??? Because when you multiply something by pi you just get a value that is multiplied by pi. Please look here and then write back with more instructions. Thnx.

[thewitch]

sorry i guess i did make that a little complicated
im supposed to graph y=tan(pi*x)+2

i set up my table like this for the graph

x,y untraslated = -3pi/4,1 -pi/2,undefined -pi/4 0,-1 pi/4,undefined pi/2,1 3pi/4,-1

i understand you just add 2 to the y coordinate but i do not know how i would translate the x cordinate on the graph

[maggiemagnet]

i do not know how i would translate the x cordinate on the graph

That's what they show in the link the other poster gave you. They've got pictures there, too! Please do take a look; it's probably quicker (and a lot easier to understand!) than us trying to put it into words.

[thewitch]

Yes I read the link completely the problem I am having is that it doesn't tell me what the pi does on the inside to the variables. I understand everything about graphing it and all i just don't know what the pi next to x does to each value

[maggiemagnet]

Yes it does: the multiplier inside (on the variable) is the "B" that tells you the length of the period. In this case, since B = pi, then the period (2pi)/(pi) = 2. Do the axis-labelling trick they show, and there you are!