**We have been give the equation of the line where the point (3,2) lies and we have to find the point on that line which is 5 units away from (3,2)? The equation of the line is 4y -3x+1=0.**

Solve 4y - 3x + 1 = 0 for y. Plug the point (3, 2) and the point (x, y) into The Distance Formula (using the expression for y that you got when you solved). Put the distance equal to 5. Square both sides and solve for the x coordinates of the two points on the line. Then plug back into the expression for y to find the y coordinates for each of the two points. This is your answer.We have been give the equation of the line where the point (3,2) lies and we have to find the point on that line which is 5 units away from (3,2)? The equation of the line is 4y -3x+1=0.

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