Hello,

tanA = -2/6

a. Draw two possible locations on the coordinate axis for the terminal arm of angle A

b. Find two possible values for the measure of angle A and the related acute angle.

I have done the first part of the question what I need help with is the second part

This what I have done so far:

tanA = -2/6 = tanA = -0.3

A = tan^-1 = -0.3

A = -16.7

the -16.7 angle is related to the acute angle A

Therefore angle A = 180 - (-16.7)

= 196.7.

Is this right? or Is there another way to do this?

Thanks