Solving for an variable in a denominator (with exponent)

Quadratic equations and inequalities, variation equations, function notation, systems of equations, etc.
WB67605
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Joined: Sun Feb 19, 2012 6:04 am
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Solving for an variable in a denominator (with exponent)

Postby WB67605 » Sun Feb 19, 2012 6:16 am

-1/x^2 = -4

I'm totally drawing a blank, and the only posts/lessons I've been able to find involve variables in the numerator.
If it's any help, the answer to this step is:

x^2= 1/4

I know how to solve from there, but this step is killing me. What is the process.

Thanks!

WB67605
Posts: 3
Joined: Sun Feb 19, 2012 6:04 am
Contact:

Re: Solving for an variable in a denominator (with exponent)

Postby WB67605 » Sun Feb 19, 2012 6:36 am

Success!

Simply multiply both sides by -x^2 (reciprocal of the fraction) then solve for -1 = -4x^2.

Thanks anyway!


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