Motherof8 wrote:Here's the problem: The perimeter of a rectangle is 56 ft. The diagonal is 20 ft. Find the dimensions. I made this formula:
2(x + y) = 56 x squared + y squared = 400 (20 squared) but I don't know what to do from there.
well first of all divide 56 by two to get 28. now you have o find the two numers that square to 400 and add to 28. now im pretty sure you can do this with an equation but i forgot it and thus did guess and check and found the dimentions to be 12 and 16.
PROOF: 12+16=28 and 12 squared is 144, 16 squared is 256, 144+256=400