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y=f(x)= -2x^2+12x-10 represent a parabola. Determine (a)the vertex (b) x and y intercepts (c) the maximum value of y and (d) sketch the graph of the parabola

- tphillips9
**Posts:**2**Joined:**Tue Dec 01, 2009 9:09 pm

Either complete the square to find the vertex, or else use the formula.

To find the x-intercepts, plug zero in for y. To find the y-intercepts, plug zero in for x.

The maximum will be the y-value of the vertex.

To graph, draw the vertex and the intercepts, and plot a few more points. Then draw the graph.

To find the x-intercepts, plug zero in for y. To find the y-intercepts, plug zero in for x.

The maximum will be the y-value of the vertex.

To graph, draw the vertex and the intercepts, and plot a few more points. Then draw the graph.

- nona.m.nona
**Posts:**256**Joined:**Sun Dec 14, 2008 11:07 pm

is the vertex 1/8 and the x and y intercept is (1/2,0) or (-10,0) and y is (0,10)

- tphillips9
**Posts:**2**Joined:**Tue Dec 01, 2009 9:09 pm

The vertex is supposed to be a point, (x, y) = (h, k). Try using the formula to get the value of h, and then plug that into f(x) to find the value of k.

To find the intercepts, plug in zeroes where appropriate. To find the x-intercepts, either factor or else use the Quadratic Formula. To find the y-intercept, simply evaluate.

If you are unsure of your answers, please reply showing your work. Thank you.

To find the intercepts, plug in zeroes where appropriate. To find the x-intercepts, either factor or else use the Quadratic Formula. To find the y-intercept, simply evaluate.

If you are unsure of your answers, please reply showing your work. Thank you.

- nona.m.nona
**Posts:**256**Joined:**Sun Dec 14, 2008 11:07 pm

4 posts
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