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From Descarte's rule of signs, conclude that the equation x^(2n) -1=0 has 2n-2 imaginary roots

- mepomero
**Posts:**1**Joined:**Mon Jan 20, 2014 1:48 am

mepomero wrote:From Descarte's rule of signs, conclude that the equation x^(2n) -1=0 has 2n-2 imaginary roots

You know that the equation must have 2n roots, due to the degree. What real roots did you find when you applied graphing, experience, or the Rational Roots Test? What did you determine when you applied Descartes' Rule of Signs to this polynomial equation? Thank you.

- nona.m.nona
**Posts:**256**Joined:**Sun Dec 14, 2008 11:07 pm

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