suppose f(-3)=5/8 and f(2)=20. Find a formula for f assuming it is
a. linear y=mx +b so slope was 155/8. If I put it into the formula y=19 3/8x -18 3/4
b. exponential
f(20) =20. P=f(t)=ab^{t}
f(2)=ab_{2}=20
f(-3)=ab^{-3}=5/8
then put one equation over th eother to get b^{5}=32, so b=2
is this correct?