A curve with the equation: y= 3x^2 - x^3

tangent drawn at point (3,0)

how to find the gradient?

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A curve with the equation: y= 3x^2 - x^3

tangent drawn at point (3,0)

how to find the gradient?

tangent drawn at point (3,0)

how to find the gradient?

- Nats
**Posts:**18**Joined:**Mon Aug 19, 2013 11:14 am

Nats wrote:A curve with the equation: y= 3x^2 - x^3

tangent drawn at point (3,0)

how to find the gradient?

i think you'd need calculus for this. but what you've posted shows you're probably still in early algebra. what class is asking all these questions???

- buddy
**Posts:**121**Joined:**Sun Feb 22, 2009 10:05 pm

Im taking Cambridge IGCSE Mathematics (0581)

This is a question for my assignment. the graph is already drawn.

This is a question for my assignment. the graph is already drawn.

- Nats
**Posts:**18**Joined:**Mon Aug 19, 2013 11:14 am

Nats wrote:Im taking Cambridge IGCSE Mathematics (0581)

This is a question for my assignment. the graph is already drawn.

what method do they teach you for finding the gradient at a point on a curved line? i only know calc so you need to say what other thing you're supposed to use. thnx

- buddy
**Posts:**121**Joined:**Sun Feb 22, 2009 10:05 pm

what method do they teach you for finding the gradient at a point on a curved line? i only know calc so you need to say what other thing you're supposed to use. thnx

In my textbook it states: to calculate the gradient of a curve at a specific point, the following steps need to be taken:

*draw a tangent to the curve at the point

*calculate the gradient of the tangent

worked example : y = 2x^2, calculate the gradient of the curve at the point when x= 1

and then two graphs are given. a tangent is drawn at x =1

two points on the tangent are identified in order to calculate its gradient

gradient =10 - (-2) /3-0

12/3

=4

gradient of function y = 2x^2 is 4.

and thats it then it gives us exercises to complete.

is there any way i can post images on this post? so i can show you the graph to the question im asking?

In my textbook it states: to calculate the gradient of a curve at a specific point, the following steps need to be taken:

*draw a tangent to the curve at the point

*calculate the gradient of the tangent

worked example : y = 2x^2, calculate the gradient of the curve at the point when x= 1

and then two graphs are given. a tangent is drawn at x =1

two points on the tangent are identified in order to calculate its gradient

gradient =10 - (-2) /3-0

12/3

=4

gradient of function y = 2x^2 is 4.

and thats it then it gives us exercises to complete.

is there any way i can post images on this post? so i can show you the graph to the question im asking?

- Nats
**Posts:**18**Joined:**Mon Aug 19, 2013 11:14 am

5 posts
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