## simplifying real numbers and algebaric terms and expression

Simple patterns, variables, the order of operations, simplification, evaluation, linear equations and graphs, etc.

### simplifying real numbers and algebaric terms and expression

i am very new to the algebra thing and i don't know nothing about it i have tried looking it up but still not having any clues at all now i have college algebra and i am so confused. i never had this in school before so it is all new to me PLEASE HELP!!!!!
lenora

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Joined: Wed Jul 24, 2013 12:50 am

lenora wrote:i am very new to the algebra thing and i don't know nothing about it i have tried looking it up but still not having any clues at all now i have college algebra and i am so confused. i never had this in school before so it is all new to me PLEASE HELP!!!!!

Did you have a specific question from your course's homework?

stapel_eliz

Posts: 1797
Joined: Mon Dec 08, 2008 4:22 pm

### Re: simplifying real numbers and algebaric terms and express

So, now you are studying College Algebra and it is difficult to learn and to study.

Two things you need to have very well developed are, (!) Strong attention to written English syntax and sentence mechanics both for reading comprehension and for attention to how you express what you wish to say, and (!) a general understanding of Algebra at least through most of Intermediate Algebra, which includes very good skills and understanding of Algebra 1 (elementary Algebra). You learn properties of real numbers, and learn several other things about using variables and variable terms, and some graphical number relationships.

Take care of those two things and then you will be ready for College Algebra. The course is not suitable for someone who has no understanding of basic arithmetic nor beginning algebra.
jg.allinsymbols

Posts: 75
Joined: Sat Dec 29, 2012 2:42 am

### Re: simplifying real numbers and algebaric terms and express

When you are simplifying real numbers, you are actually simplifying the expression or equation given. To do so, many people use the PEMDAS method. This method stands out:
P for parenthesis
E for exponents
M for multiplication
D for division
S for subtraction

However, whenever you face with an equation that has both division and multiplication next to each other, you must remember that you have to do at left to right. This same rule applies for both addition and subtraction.

Let us do a sample so that you can fully understand what I am trying to express. This equation is pretty much a beginner's equation, but this is actually the centre for you to understand and manoeuvre the perspective of simplifying.

Okay, let's say that we had to solve: 12/(2*2)*5-2+9

Lets do this problem step-by-step.

1) According to the PEMDAS method, we first have to see if there is any parentheses because that is the first thing that needs to be evaluated. Since there is one that is surrounding both 2's, we need to evaluate that first. Since we know that 2*2=4, we then have the expression like this: 12/4*5-2+9.

2) When we see this problem, we know that there is a multiplication and division problem that is right next to each other. Since these two are next to each other, you need to make sure that we do this problem left to right. Meaning that we have to do division first rather than doing the multiplication equation. So we have to do 12/4=3. The expression will then be:
3*5-2+9. Now it is time to do 3*5=15. So the expression will later be: 15-2+9.

3) So then we now see that we have both a subtraction and addition equations side-by-side. Since we have to do this problem from left to right, we have to compute 15-2, in which the difference will be 13. Then, we do 13+9, since 13 replaced both 15 and 2. The sum will be then 22. So our final answer is 22.

Hope you learned the prospect of simplifying and evaluating expressions.
uktime

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Joined: Sat Jul 20, 2013 8:46 pm