Alright so here's the question:

Express log x in terms in log a, log b, and log c.

X=(ab)^3/c

(ab cubed All over c)

Not sure how to approach this. Do I make it log(ab)^3 or log(a)*log(b)^3 ?

5 posts
• Page **1** of **1**

Alright so here's the question:

Express log x in terms in log a, log b, and log c.

X=(ab)^3/c

(ab cubed All over c)

Not sure how to approach this. Do I make it log(ab)^3 or log(a)*log(b)^3 ?

Express log x in terms in log a, log b, and log c.

X=(ab)^3/c

(ab cubed All over c)

Not sure how to approach this. Do I make it log(ab)^3 or log(a)*log(b)^3 ?

- Hell0
**Posts:**24**Joined:**Sun Jun 23, 2013 5:04 am

Hell0 wrote:Express log x in terms in log a, log b, and log c.

X=(ab)^3/c

(ab cubed All over c)

"X" means "x", right? (That's not the way its "supposed" to be so I'm asking.)

Hell0 wrote:Do I make it log(ab)^3 or log(a)*log(b)^3 ?

The cube is on the product, not only the b, so the powers work like this: (ab)^3 = (a^3)(b^3)

- FWT
**Posts:**107**Joined:**Sat Feb 28, 2009 8:53 pm

Yeah sorry that's what I meant. And yes X means x

- Hell0
**Posts:**24**Joined:**Sun Jun 23, 2013 5:04 am

Hell0 wrote:Yeah sorry that's what I meant. And yes X means x

Okay, so you have log(x) = log((ab)^3 / c). Turn the dividing into subtracting. Then turn the (ab)^3 into a^3 b^3 and turn the multiplying into adding. Then turn the powers intyo coefficients. (Use the rules here.) Plz write back if you're stuck.

- FWT
**Posts:**107**Joined:**Sat Feb 28, 2009 8:53 pm

Thanks . I totally misunderstood the question

- Hell0
**Posts:**24**Joined:**Sun Jun 23, 2013 5:04 am

5 posts
• Page **1** of **1**