Product involving a difference as an exponent  TOPIC_SOLVED

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Product involving a difference as an exponent

Postby mathstuff on Wed Apr 03, 2013 3:00 am

I'm learning discrete math, but having a problem with an algebraic simplification, so I think I'm posting this in the right place.

2(2n-1) = 2n but I don't see how this is.

It seems to me that 2(2n-1) = 4n-1

What is the rule at work here?
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Re: Product involving a difference as an exponent  TOPIC_SOLVED

Postby little_dragon on Wed Apr 03, 2013 5:32 pm

mathstuff wrote:2(2n-1) = 2n but I don't see how this is.

It seems to me that 2(2n-1) = 4n-1

What is the rule at work here?

do the regular exponent stuff: http://www.purplemath.com/modules/exponent.htm
it's 2(2n-1) not (2*2)n-1 so it can't be 4-to-something, at least not right away and n would have to be even.
it's (21)(2n-1) so you add powers.
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