Please, help me solve this intergral:

Int (x^2 + 2x - 3) / (x + 1) dx,

when x > -1

Thank you.

Please, help me solve this intergral:

Int (x^2 + 2x - 3) / (x + 1) dx,

when x > -1

Thank you.

Int (x^2 + 2x - 3) / (x + 1) dx,

when x > -1

Thank you.

- stapel_eliz
**Posts:**1686**Joined:**Mon Dec 08, 2008 4:22 pm-
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mitnord wrote:Int (x^2 + 2x - 3) / (x + 1) dx, when x > -1

By

. . . . .

The polynomial part is simple enough to integrate.

For the rational part, a simple substitution should work:

. . . . .

Then integrate (-4)(1/u), and back-substitute.