Question about sum and difference of cubes  TOPIC_SOLVED

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Question about sum and difference of cubes

Postby geramul on Wed Oct 24, 2012 10:21 am

Hi this is my first post here. First off I want to express my immeasurable gratitude to this site as it has helped me a lot.

I have a question about as my thread title states, the sum and difference of cubes. The sample question to factor x3y6 – 64 confuses me. I tend to over think things in math a bit sometimes, so I'm sorry if my questions seem a bit ridiculous. Now I have two questions for this problem.

1. This one may seem silly, but I want to absolutely make sure about this. Really you can't be too careful with math now can you? the formula for sum and difference of cubes is a3 + b3 = (a + b)(a2 – ab + b2), yes? Now, x3y6 turns into, (xy2)3. Could I have looked at this problem before as (a)(b) - (c), and therefore that is why x and y came together to become (a) - (c) as part of the factoring process?

2. My other question is why does x3y6 become (xy2)3? It doesn't make sense to me. I mean I understand part of the reason, but let me explain further. If I'm bringing x3y6 together, that should make it xy9, right? Now I see where the 2 and 3 are coming from, but if I try to multiply it back together I get 8 not 9. Of course I could be COMPLETELY wrong about the way I'm going about this :l.

I feel so silly not being able to figure this out.
geramul
 
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Re: Question about sum and difference of cubes

Postby theshadow on Wed Oct 24, 2012 11:52 am

geramul wrote:the formula for sum and difference of cubes is a3 + b3 = (a + b)(a2 – ab + b2), yes? Now, x3y6 turns into, (xy2)3. Could I have looked at this problem before as (a)(b) - (c), and therefore that is why x and y came together to become (a) - (c) as part of the factoring process?

What do you mean by "(a)(b) - (c)"?

geramul wrote:If I'm bringing x3y6 together, that should make it xy9, right?

No. Powers don't work that way. Look here and here.
theshadow
 
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Re: Question about sum and difference of cubes  TOPIC_SOLVED

Postby geramul on Thu Oct 25, 2012 11:08 am

I think I figured it out on my own. x3y6 becomes (xy2)3 because the three is getting factored out right? I hope that's right :l.
geramul
 
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