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by **Tomtom** on Wed Oct 17, 2012 9:01 pm

3^5(3^-2 + 3^-3)
______________
9

Hope this explains as I was unable how to figure out how to make exponents on my laptop.

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by **stapel_eliz** on Fri Oct 19, 2012 1:08 am

Tomtom wrote: $\frac{3^5\left(3^{-2}\, +\, 3^{-3}\right)}{9}$

Where are you stuck? You converted the negative exponents to positives, converted the fractions to common denominators, simplified, and... then what?

. . . . . $\frac{3^5\left(\frac{1}{3^2}\, +\, \frac{1}{3^3}\right)}{3^2}\, =\, \frac{\frac{3^5}{1}\left(\frac{3}{3^3}\, +\, \frac{1}{3^3}\right)}{\frac{3^2}{1}}$

Please be complete. Thank you!

Tomtom wrote:Hope this explains as I was unable how to figure out how to make exponents on my laptop.

To learn how to format math as text, please review this article. :wink:

by **Tomtom** on Mon Oct 22, 2012 12:27 pm

Sorry my apologies,I neglected to write that I have no idea to solve.

by **stapel_eliz** on Tue Oct 23, 2012 1:17 am

Tomtom wrote:Sorry my apologies,I neglected to write that I have no idea to solve.

If you mean "simplify", then a good start would probably be with the steps listed earlier. Two steps have already been given to you. :wink:

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