4^1-3b=8^2b+1

appreciate the help

4^1-3b=8^2b+1

appreciate the help

appreciate the help

- stapel_eliz
**Posts:**1628**Joined:**Mon Dec 08, 2008 4:22 pm-
**Contact:**

sanman777 wrote:4^1-3b=8^2b+1

appreciate the help

I would assume that the instructions were something along the lines of "solve the equation". Unfortunately, your

Before we can know whether or not this can be solved algebraically, you'll need to provide clarification of what the equation is. For instance, does "8^2b+1" mean "8

When you reply, please include a clear listing of your steps and reasoning so far. Thank you!

it says to solve algebraically

- stapel_eliz
**Posts:**1628**Joined:**Mon Dec 08, 2008 4:22 pm-
**Contact:**

4^1-3b=8^2b+1

- stapel_eliz
**Posts:**1628**Joined:**Mon Dec 08, 2008 4:22 pm-
**Contact:**

sanman777 wrote:4^1-3b=8^2b+1

I'm going to guess that the above means the following:

. . . . .4^(1 - 3b) = 8^(2b + 1)

(If you're not wanting to use

The trick for solving this sort of

. . . . .

Since 27 = 3

. . . . .

. . . . .

The equation can then be restated as:

. . . . .

Equate the powers:

. . . . .

...and solve the resulting linear equation.

Your exercise works the exact same way.

kk thanks alot