Quadratic equations and inequalities, variation equations, function notation, systems of equations, etc.
quaz7829
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Joined: Tue Sep 25, 2012 12:55 am
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Can anyone help me? It is a word problem I am stuck on.

A square poster has sides measuring 2 feet less than the sides of a square sign. If the difference between there areas is 12 sq feet, find the lengths of the sides of the poster and sign.

so far all i have figured out is (x-2)*(x-2)=x^2 if some one could help i would appreciate that.

maggiemagnet
Posts: 358
Joined: Mon Dec 08, 2008 12:32 am
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A square poster has sides measuring 2 feet less than the sides of a square sign. If the difference between there areas is 12 sq feet, find the lengths of the sides of the poster and sign.

so far all i have figured out is (x-2)*(x-2)=x^2 if some one could help i would appreciate that.
I think you are using "x" to be "the length of the sides of the sign", so "x - 2" is "the length of the sides of the poster". The left side of your equation is "the area of the poster" and the right side is "the area of the sign". But are these areas the same?