4^1-3b=8^2b+1

appreciate the help

4^1-3b=8^2b+1

appreciate the help

appreciate the help

- stapel_eliz
**Posts:**1628**Joined:**Mon Dec 08, 2008 4:22 pm-
**Contact:**

I would assume that the instructions were something along the lines of "solve the equation". Unfortunately, your4^1-3b=8^2b+1

appreciate the help

Before we can know whether or not this can be solved algebraically, you'll need to provide clarification of what the equation is. For instance, does "8^2b+1" mean "8

When you reply, please include a clear listing of your steps and reasoning so far. Thank you!

it says to solve algebraically

- stapel_eliz
**Posts:**1628**Joined:**Mon Dec 08, 2008 4:22 pm-
**Contact:**

4^1-3b=8^2b+1

- stapel_eliz
**Posts:**1628**Joined:**Mon Dec 08, 2008 4:22 pm-
**Contact:**

I'm going to guess that the above means the following:4^1-3b=8^2b+1

. . . . .4^(1 - 3b) = 8^(2b + 1)

(If you're not wanting to use

The trick for solving this sort of

. . . . .

Since 27 = 3

. . . . .

. . . . .

The equation can then be restated as:

. . . . .

Equate the powers:

. . . . .

...and solve the resulting linear equation.

Your exercise works the exact same way.

kk thanks alot