Note to poster: As you read in the "Read Before Posting" message, volunteers do not "do" students' work for them, nor do they give out answers. Students need to show at least some effort toward the solutions.

D'oh!! I'd been SURE I put those in before I hit submit...what happened? O_O Ah well. I'll just re-type them again I guess.

Also, please clarify the first "Question 3" below. In particular, are you needing to find the probability that the random point is six units "from" Q, or the probability that the point is "within" six units "of" Q? (As currently posted, the English doesn't make sense.)

That is exactly the reason why I can't solve it. That is what the questions say, word-by-word, on the problem sheet. No clarifications at all :(

2) Points A, B, C, and D are on a straight line in that order, and there is a point P not on this line such that PD = (5/2)PB and AB = CD. If the area of triangle PAB is 100 square units, find the area of triangle PCD.

I get that the area of a triangle is (bh)/2, so if AB=x, 200/x=height. Since AB=CD, CD=x too. That's all that I can work out from the given @_@

I don't get how PD=(5/2)PB is related. is PD Triangle PDC's height? If so, then is PB triangle PBA's height?

3) Draw a diagram in which F is between A and E, F is also between R and S, but A, E, R, and S are non-collinear.

I don't see how it's possible to diagram these if they're all non-collinear. If there are more than three points, then are they all non-collinear if only one point lies outside the line the others are on? Or does that mean that none of them must ever be in the same line?

4) The coordinate of P, Q, and R are -6, 20, and 24, respectively. If a point is chosen at random on segment PR, what is the probability that it is six units of Q?

Like I said, I don't know how to approach this because it isn't clarified if it means "six units from Q" or "within six units of Q".

Congruent Angles:

3) Two lines bisect consecutive angles of a regular heptagon and intersect in the heptagon's interior. Find the measures of the angles formed by the intersecting lines.

What does 'consecutive angles' mean? Two angles beside/adjacent to each other? If it's a regular heptagon, then they must be equal. So the bisectors should probably be equal too, right? But what is the measure of one angle in a right heptagon? I don't know. :(

4) Ray BE bisects angle A of DABC and ray CE bisects angle C of DABC. If the measure of angle A is 84 degrees, find the measure of the angle formed by the intersecting rays BE and CE.

What kind of figure is DABC anyways? I'm fairly sure I could answer this, but I can't visualize the problem properly.

Angle Pairs:

3) The ratio of the complements of two angles is 3 : 2, and the ratio of their supplements is 9 : 8. Find the [measures of] the two original angles.

No need to answer. I solved it already