Hi all,
How do you find out if this Parametric equation
x = -2t + 3 ; y = -t - 1 ; z = -3t + 2
Is perpendicular to this parametric equation
x = -2 + 6t ; y = 3 - 6t ; z = -3 - 2t
Thanks
The planes determined by the vectors corresponding to these parametric equations will intersect at an angle A of 90* (or pi/2), as will their normal vectors. So apply the formulaHow do you find out if this Parametric equation
x = -2t + 3 ; y = -t - 1 ; z = -3t + 2
Is perpendicular to this parametric equation
x = -2 + 6t ; y = 3 - 6t ; z = -3 - 2t