Help on evaluating expression

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Help on evaluating expression

Evaluate and simplify y=2x+1/x+1 if x=1+h

this is what i got so far,

2(1+h)+1/(1+h)+1 ---> 2+h+1/(1+h)+1

monsoon

Posts: 2
Joined: Wed May 09, 2012 5:49 pm

monsoon wrote:Evaluate and simplify y=2x+1/x+1 if x=1+h

What you have posted means this:

. . . . .$y\, =\, 2x\, +\, \frac{1}{x}\, +\, 1$

Is this what you meant? Or did you mean one of the following?

. . . . .$\mbox{a) }\, y\, =\, \frac{2x\, +\, 1}{x}\, +\, 1$

. . . . .$\mbox{b) }\, y\, =\, 2x\, +\, \frac{1}{x\, +\, 1}$

. . . . .$\mbox{c) }\, y\, =\, \frac{2x\, +\, 1}{x\, +\, 1}$

Thank you!

stapel_eliz

Posts: 1716
Joined: Mon Dec 08, 2008 4:22 pm

Re:

stapel_eliz wrote:
monsoon wrote:Evaluate and simplify y=2x+1/x+1 if x=1+h

What you have posted means this:

. . . . .$y\, =\, 2x\, +\, \frac{1}{x}\, +\, 1$

Is this what you meant? Or did you mean one of the following?

. . . . .$\mbox{a) }\, y\, =\, \frac{2x\, +\, 1}{x}\, +\, 1$

. . . . .$\mbox{b) }\, y\, =\, 2x\, +\, \frac{1}{x\, +\, 1}$

. . . . .$\mbox{c) }\, y\, =\, \frac{2x\, +\, 1}{x\, +\, 1}$

Thank you!

I meant C sorry for the confusion
monsoon

Posts: 2
Joined: Wed May 09, 2012 5:49 pm

Re: Help on evaluating expression

stapel_eliz wrote:. . . . .$\mbox{c) }\, y\, =\, \frac{2x\, +\, 1}{x\, +\, 1}$
monsoon wrote:I meant C sorry for the confusion

then I don't get how you got the step you showed
plug the "1+h" in for all the "x"s
$y\, =\, \frac{2(1+h)\, +\, 1}{(1+h)\, +\, 1}$
like, how did you get 2(1+h)=(2)(1)+(2)(h) equal to 2+h not 2+2h?
thnx
buddy

Posts: 125
Joined: Sun Feb 22, 2009 10:05 pm