Here is the problem: If "a" and "b" are not both 0, show that the points (2b,a),(b,b), and (a,0) are the vertices of a right triangle.
Do I need to solve for the variables given or can I just plug in any number?
richierichard wrote:Here is the problem: If "a" and "b" are not both 0, show that the points (2b,a),(b,b), and (a,0) are the vertices of a right triangle.
Do I need to solve for the variables given or can I just plug in any number?
little_dragon wrote:U get
d^2=(2b-b)^2+(a-b)^2=b^2+a^2-2ab+b^2=2b^2-2ab+a^2
d^2=(2b-a)^2+(a-0)^2=4b^2-4ab+a^2+a^2=4b^2-4ab+2a^2
d^2=(a-b)^2+(0-b)^2=a^2-2ab+b^2+b^2=2b^2-2ab+a^2
U can see wat U get when U add!