Lesson Dealing with Logs: Solve 5^(3x) = 25^(2x+1)

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mawarbalow
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Lesson Dealing with Logs: Solve 5^(3x) = 25^(2x+1)

Postby mawarbalow » Wed Jan 25, 2012 12:26 am

Hi,
Here is my problem:
Solve: 5^(3x) = 25^(2x+1)

I honestly don't know what to do. I've been sick and we have a test coming up! I would guess that somehow you have to get the x's down from being an exponent and get them both on one side. Any help would be great! :)

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maggiemagnet
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Re: Lesson Dealing with Logs: Solve 5^(3x) = 25^(2x+1)

Postby maggiemagnet » Wed Jan 25, 2012 12:42 pm

mawarbalow wrote:Solve: 5^(3x) = 25^(2x+1)

I honestly don't know what to do.

Then try the lesson here! Step 1: Convert "25" into "52".
:clap:


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