Solving for "y"

Simple patterns, variables, the order of operations, simplification, evaluation, linear equations and graphs, etc.
mrscobb
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Solving for "y"

Postby mrscobb » Thu Sep 01, 2011 2:01 pm

Help! I know this is very simple...I need to solve for "y". But I don't understand how to "flip" the problem into fraction form to solve. Any guidance is appreciated!! :D

4y=3

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maggiemagnet
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Re: Solving for "y"

Postby maggiemagnet » Thu Sep 01, 2011 5:58 pm

mrscobb wrote:I need to solve for "y". But I don't understand how to "flip" the problem into fraction form to solve. Any guidance is appreciated!

You can learn how to do this here!
:clap:

fadhil
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Re: Solving for "y"

Postby fadhil » Mon Jan 23, 2012 6:25 pm

The equation: 4y=3

The frist thing is to make sure that only 'y' or the 'unknown(s)' remain in one side and the number types(... -2,-1, 0, 1, 2, ...) the other side.
The second thing is to make sure that what is done to one side of the equation is equally done to the other.

4y = 3

In order to make 'y' remains on one side, we find a way to eliminate '4' from 'y'

Then, dividing 4y by 4 will eliminate 4, given 4/4 = 1 . So 1y = y

Remember, what we did to left side of equation unknown or 'y' must be done to the right side of the equation that has 3. That is, dividing the right side of the equation by 4 as well. Given 3/4

4/4y = 3/4 , which gives 1y = 3/4. Since 1y = y , y = 3/4


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