## Find the x and y intercepts

Quadratic equations and inequalities, variation equations, function notation, systems of equations, etc.
jpalmer11
Posts: 7
Joined: Thu Sep 08, 2011 5:20 pm
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### Find the x and y intercepts

Hi,

I am having problems with two problems I am hoping someone can point me in the right direction.

First find the x intercepts and y intercepts for f(x)

f(X)=x^2-6x+1

second solve for x

x^2+41=10x (type your answer in the form a+bi)

I understand the basic concepts, but the answers I am coming out with do not look right.
I would be grateful for any help.
Thank You

stapel_eliz
Posts: 1731
Joined: Mon Dec 08, 2008 4:22 pm
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jpalmer11 wrote:First find the x intercepts and y intercepts for f(x)

f(X)=x^2-6x+1

second solve for x

x^2+41=10x (type your answer in the form a+bi)

I understand the basic concepts, but the answers I am coming out with do not look right.

It's hard to find errors in work we can't see.

Please reply showing what you're "coming out with", and the steps you took to get there. Thank you!

jpalmer11
Posts: 7
Joined: Thu Sep 08, 2011 5:20 pm
Contact:

### Re: Find the x and y intercepts

Thank you so much for getting back to me. Sorry about that it was real late and I was not thinking clearly. I will as soon as I get home.

jpalmer11
Posts: 7
Joined: Thu Sep 08, 2011 5:20 pm
Contact:

### Re: Find the x and y intercepts

For f(x)=x^2-6x+1
I think the reason I can not find the X and Y intercepts is there are no intercepts. Is that correct.

on the second problem solve for x
x^2+7x-4=0
can you just let me know if I am heading in the right direction with
- (-10) + 2 the square of 10^2 - 164 devided by 2
Thank You

stapel_eliz
Posts: 1731
Joined: Mon Dec 08, 2008 4:22 pm
Contact:
jpalmer11 wrote:For f(x)=x^2-6x+1
I think the reason I can not find the X and Y intercepts is there are no intercepts. Is that correct.

To find the x-intercept(s), plug zero in for y (in this case, for f(x)) and solve. What do you get?

To find the y-intercept, plug zero in for x and solve. What do you get?

Note: You can also look at the graph to confirm the intercept(s), if any.

jpalmer11 wrote:on the second problem solve for x
x^2+7x-4=0
can you just let me know if I am heading in the right direction with
- (-10) + 2 the square of 10^2 - 164 devided by 2

Your formatting is unclear, and I have no idea what is meant by the squared "plus" sign. Do you maybe mean the following?

. . . . .(-(-10) +/- sqrt[10^2 - 164]) / 2

...which typesets as:

. . . . .$\frac{-(-10)\, \pm\, \sqrt{10^2\, -\, 164}}{2}$

If so, how did you get this? I'm not seeing how this relates to the Quadratic Formula or any other method of solving this quadratic equation (which has a = 1, b = 7, and c = -4)...?