jpalmer11 wrote:For f(x)=x^2-6x+1

I think the reason I can not find the X and Y intercepts is there are no intercepts. Is that correct.

To find the x-intercept(s), plug zero in for y (in this case, for f(x)) and solve. What do you get?

To find the y-intercept, plug zero in for x and solve. What do you get?

Note: You can also look at the graph to confirm

the intercept(s), if any.

jpalmer11 wrote:on the second problem solve for x

x^2+7x-4=0

can you just let me know if I am heading in the right direction with

- (-10) + ^{2} the square of 10^2 - 164 devided by 2

Your

formatting is unclear, and I have no idea what is meant by the squared "plus" sign. Do you maybe mean the following?

. . . . .(-(-10) +/- sqrt[10^2 - 164]) / 2

...which typesets as:

. . . . .If so, how did you get this? I'm not seeing how this relates to

the Quadratic Formula or any other method of solving this quadratic equation (which has a = 1, b = 7, and c = -4)...?