Algebra - systems word problem  TOPIC_SOLVED

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Algebra - systems word problem

Postby Divine on Thu Nov 10, 2011 12:03 pm

The math question in my book that I'm inquiring about has a picture, so I took a picture and uploaded the question. It's #65.

http://uploadpic.org/v.php?img=wBAwPTzp7I

I've only got two linear equations in 3 variables. I needed one more to create a system of 3 equations in 3 variables.

This is what I did to get the two equations,

L = length of the wood
w = width of the wood
h = height of the table

-L + 32 + w = h
-w + 28 + L = h

The only other fact that I could determine besides those equations was this:

(-L +32 + w) + (-w + 28 +L) = 2h

This just states that if you add the two equations together, they equal twice the height. However, this solves to h = 30 cm because w and L cancel each other out, making it impossible to be used in my system.

30cm is the height, but what's weird is that I determined this without even making a system. I need to know how to get the system though, so that I can figure out L and w.

I'm really determined to figure this out, so help would be appreciated. :)
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Re: Algebra - systems word problem  TOPIC_SOLVED

Postby maggiemagnet on Sun Nov 13, 2011 11:25 pm

Divine wrote:L = length of the wood
w = width of the wood
h = height of the table

-L + 32 + w = h
-w + 28 + L = h

You can kind of cheat. Since you don't actually care what L and w are, you can do "L - w = x". Then you have these equations:

. . . . .32 - x = h
. . . . .28 + x = h

Then 60 = 2h, and so forth.
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