Having trouble factoring this expression...

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ReviewStudent
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Having trouble factoring this expression...

Postby ReviewStudent » Fri Sep 09, 2011 11:22 pm

I am trying to review through self-study, but am having difficulty factoring this expression (despite having some help).

The Expression:
2x^2(x+3) + 4x(x+3)^2

Their method of factoring is as follows:
2x(x+3)[x+2(x+3)]
= 2x(x+3)(3x+6)
= 2x(x+3)3(x+2)
= 6x(x+3)(x+2)


Any suggestions or links I can follow? Any help would be greatly appreciated.

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stapel_eliz
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Postby stapel_eliz » Sat Sep 10, 2011 1:53 am

ReviewStudent wrote:The Expression:
2x^2(x+3) + 4x(x+3)^2

Their method of factoring is as follows:
2x(x+3)[x+2(x+3)]
= 2x(x+3)(3x+6)
= 2x(x+3)3(x+2)
= 6x(x+3)(x+2)

If what you've posted is the complete worked solution, then I'd say it's no wonder you're confused! After the initial expression, they should have provided the first step in the solution:

. . . . .

Between the first and second line in their solution, they probably should have shown the step were the 2 inside the square brackets is multiplied through the x + 3, so the simplification inside the square brackets makes more sense. After that, though, they've pretty much shown what's needed. :wink:

ReviewStudent
Posts: 4
Joined: Fri Sep 09, 2011 11:09 pm
Contact:

Re: Having trouble factoring this expression...

Postby ReviewStudent » Sun Sep 11, 2011 11:07 pm

Oh, thanks :D . It makes sense now, haha.


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