sully039 wrote:I'm not sure if I'm suppossed to find the value of 5pi/6 (which is 1/2) and then subtract 2pi from it. Or is it sin(5pi/6)-sin(2pi)?

Wow! They were supposed to teach you about functions before diving so deep into trig! To get up to speed, try a lesson on

functions and another on

function notation. Specifically, you'll see that the parentheses in function notation is

not the same as parentheses for multiplication!

In this case, you have the function, sine, being taken of the simplified value of -pi/6.

Since the graph is already flexed back downward (in other words, it's not in the middle of its flexing) at (0, -1), then the function isn't going to be tan(something) - 1. It looks to me like you have a phase shift going on, but that's about all.

In f(x) = tan(x), what is the value of tan(-pi/4)? How can you relate that to the graph?