How to solve v - v(v - 1)/4 + (v^2 - 5)/5 + (1/20)v^2 = 0

[MathDrudge]

What is the second term? a mixed number made up by variables? or is it v * (v-1)/4? or is it either?

There are still no mixed numbers in this equation. To learn what "terms" are, please try this lesson.

To learn how to simplify v(v - 1), please try this lesson or this lesson.

is the solution for v(v-1) = v^2-v ?

[stapel_eliz]

is the solution for v(v-1) = v^2-v ?

If, by "solution", you mean "the multiplied-out form", then yes.

[MathDrudge]

i still dont know what to do with this

[stapel_eliz]

i still dont know what to do with this

Multiply it out. Cancel the four with the twenty.

[MathDrudge]

i still dont know what to do with this

Multiply it out. Cancel the four with the twenty.

[stapel_eliz]

Almost. Use the correct multiplication from two posts before the above-quoted one.