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by **MathDrudge** on Tue Jul 26, 2011 2:05 pm

stapel_eliz wrote:
MathDrudge wrote:What is the second term? a mixed number made up by variables? or is it v * (v-1)/4? or is it either?

There are still no mixed numbers in this equation. To learn what "terms" are, please try this lesson.

To learn how to simplify v(v - 1), please try this lesson or this lesson.

is the solution for v(v-1) = v^2-v ?

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by **stapel_eliz** on Tue Jul 26, 2011 8:06 pm

MathDrudge wrote:is the solution for v(v-1) = v^2-v ?

If, by "solution", you mean "the multiplied-out form", then yes. :wink:

by **MathDrudge** on Thu Jul 28, 2011 4:17 pm

i still dont know what to do with this

$20(v\, \frac{v\, -\, 1}{4}\) \,$

by **stapel_eliz** on Thu Jul 28, 2011 6:49 pm

MathDrudge wrote:i still dont know what to do with this

$20(v\, \frac{v\, -\, 1}{4}\) \,$

Multiply it out. Cancel the four with the twenty. :wink:

by **MathDrudge** on Fri Jul 29, 2011 9:23 am

stapel_eliz wrote:
MathDrudge wrote:i still dont know what to do with this

$20(v\, \frac{v\, -\, 1}{4}\) \,$

Multiply it out. Cancel the four with the twenty.

$5(v^2\, -\, 1\,) \,$

by **stapel_eliz** on Fri Jul 29, 2011 11:16 am

MathDrudge wrote: $5(v^2\, -\, 1\,) \,$

Almost. Use the correct multiplication from two posts before the above-quoted one. :wink:

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How to solve v - v(v - 1)/4 + (v^2 - 5)/5 + (1/20)v^2 = 0

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