## acceleration on particles, given A is on 30-degree slope

Trigonometric ratios and functions, the unit circle, inverse trig functions, identities, trig graphs, etc.
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### acceleration on particles, given A is on 30-degree slope

There are two masses. Mass A is 0.2 kilograms, and is resting on a 30-degree slope. Mass B is 0.3 kilograms, and is hanging past the end of the slope from an inextensible string which passes over a smooth pulley.

Find the acceleration, a, of the particles when released from rest.

"T" is the tension in the string. Then

0.3g - T = 0.3a
T - 0.2g * sin(30 degrees) = 0.2a

But the answer doesn't match the back of the book. What did I do wrong?

stapel_eliz
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Joined: Mon Dec 08, 2008 4:22 pm
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"T" is the tension in the string. Then...

T - 0.2g * sin(30 degrees) = 0.2a
Isn't the acceleration "a" on Mass A the tension on the string plus the amount of "pull" that gravity exerts as A slides down the slope...?