Logarithmic Eqns: log3 (x+6) + log3 (x-6) - log3 x = 2

Complex numbers, rational functions, logarithms, sequences and series, matrix operations, etc.
dfogelberg
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Logarithmic Eqns: log3 (x+6) + log3 (x-6) - log3 x = 2

Postby dfogelberg » Sat Jul 09, 2011 12:35 am

Would anyone know how to work the following log equation.

log3 (x+6) + log3 (x-6) - log3 x = 2

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maggiemagnet
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Re: Logarithmic Eqns: log3 (x+6) + log3 (x-6) - log3 x = 2

Postby maggiemagnet » Sat Jul 09, 2011 10:03 pm

dfogelberg wrote:Would anyone know how to work the following log equation.

Yes, and you can read about it here!

dfogelberg wrote:log3 (x+6) + log3 (x-6) - log3 x = 2

First, combine the three logs on the left into one big log, using the rules explained here. Then convert the log equation from log3(big thing) = 2 into 32 = (big thing), and solve the rational equation for x.

Remember to check the answer in the original equation!!

:clap:


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