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by **dfogelberg** on Sat Jul 09, 2011 12:35 am

Would anyone know how to work the following log equation.

log3 (x+6) + log3 (x-6) - log3 x = 2

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by **maggiemagnet** on Sat Jul 09, 2011 10:03 pm

dfogelberg wrote:Would anyone know how to work the following log equation.

Yes, and you can read about it here!

dfogelberg wrote:log3 (x+6) + log3 (x-6) - log3 x = 2

First, combine the three logs on the left into one big log, using the rules explained here. Then convert the log equation from log₃(big thing) = 2 into 3² = (big thing), and solve the rational equation for x.

Remember to check the answer in the original equation!!

:clap:

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Logarithmic Eqns: log3 (x+6) + log3 (x-6) - log3 x = 2

Logarithmic Eqns: log3 (x+6) + log3 (x-6) - log3 x = 2

Re: Logarithmic Eqns: log3 (x+6) + log3 (x-6) - log3 x = 2