Would anyone know how to work the following log equation.
log3 (x+6) + log3 (x-6) - log3 x = 2
Yes, and you can read about it here!Would anyone know how to work the following log equation.
First, combine the three logs on the left into one big log, using the rules explained here. Then convert the log equation from log_{3}(big thing) = 2 into 3^{2} = (big thing), and solve the rational equation for x.log3 (x+6) + log3 (x-6) - log3 x = 2